[Rock-dev] [Rock-Ros Bridge] Create a suscriber

[Pierre Letier]

Hello,

I have the following ROS python code that suscribes to the "chatter"topic.

In Rock, I have a component that has an ouptut port that I would like to 
publish to this subscribber. The translation of the data between ROS and 
Rock is working (convertion to Float32MultiArray), but I don't find how 
to write the ruby script that will publish to ROS and I don't understand 
how to define the topic name in the rock script (I have to provide the 
topic name in the listener.py (rospy.Subscriber(...)).

Is it possible to provide an example doing this ? Do you need other 
information ?

In the documentation, there is a reference to  "connection_policy", do 
you have an example ?

The output port is named "command"

Thank you

Pierre

-- 
Pierre Letier
Robotics Engineer

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1987 - 2012

Space Applications Services NV/SA
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#!/usr/bin/env python
import rospy
from std_msgs.msg import Float64, Float32MultiArray


def callback(data):
    rospy.loginfo(rospy.get_name() + ": I heard %s" % str(data))


def listener():
    rospy.init_node('listener', anonymous=True)
    rospy.Subscriber("chatter", Float32MultiArray, callback)
    rospy.spin()


if __name__ == '__main__':
    listener()